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Worst case scenario, revisited

And here's that other viewpoint. The difference between the two methods is a little less dramatic now, but there is an aspect of shape which I think is being better shown by the superquadrics.

Looking at these three ellipsoids [2nd, 3rd, and 4rth on top row], its this one (the 3rd) which has two equal eigenvalues, and I'd say that this property is better indicated by the superquadrics than by the ellipsoid. The same applies to these tree [1st, 2nd, and 3rd in bottom row].